Question

find the cubic polynomial with the sum, of products of its zeros taken two at a time and product of its zeros are -2 , -7, -14 respectively​

Answer 1

Answer:

p(x) =  K [ $x^{3}$ + 2$x^{2}$ - 7$x$ + 14]

Step-by-step explanation:

Let the three zeroes of the polynomial be α, β, γ

Let the cubic polynomial be p(x).

p(x) = K [ $x^{3}$ - (α + β + γ)$x^{2}$  + (αβ + βγ + αγ)$x$  - (αβγ)]

p(x) = K [$x^{3}$ - (-2)$x^{2}$  + (-7)$x$  - (-14)]

p(x) =  K [ $x^{3}$ + 2$x^{2}$ - 7$x$ + 14]

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