find the cubic polynomial with the sum, sum of the product of its zeroes taken two at a time and the product of zeroes as 1, -4 ,8 respectively
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Answer:
x³-x²-4x-8
Step-by-step explanation:
alpha + beta + gama = -b/a = 1
alpha*beta + beta*gama + alpha*gama = c/a = -4
alpha*beta*gama = -d/a = 8
Let a be 1
Then b = -1 ;c= -4; d= -8
So, by ax³+bx²+cx+d = 0
it's x³-x²-4x-8
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