Math, asked by birendrssingh, 1 year ago

find the cubic polynomoal whose three zeroes are 1/1,1,-2

Answers

Answered by riddhiphogat1

Hope it helps...................................
For cubic polynomials we have the formula =
x^3 -(alpha +beeta)x^2 + (alpha×beeta +beeta ×gama+gama ×alpha)x - (alpha ×beeta ×gama)
Now put the values of the zeroes respectively.
x^3 - 1/1x^2 +1x -(-2)
Now solve it .
x^3 -1x^2 +x +2
x^3 - x^2+x+2 is your answer....
Please mark my answer as brainlist....

Anonymous: Hey Ridhi , have a look at your answer once.There is a mistake .

riddhiphogat1: No there is not

Anonymous: the formula of cubic polynomial is x³ - ( α + ß + Γ ) x² + ( αß + ßΓ + αΓ )x - αßΓ

riddhiphogat1: i have written that only

riddhiphogat1: - + - = +

riddhiphogat1: so in the last ans changed

Anonymous: You haven't written gama in the coefficient of x62

Anonymous: sorry , x^2

hiratariq77p8do6a: x^3 - x^2+x+2........

riddhiphogat1: ok

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