find the cuble polynomal whose three zeroes
3 -1, -1/3
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Answer:
cubic polynomial,
3x³-5x²-11x-6 = 0
Step-by-step explanation:
a = 3 b = -1 c = -1/3 x²-(a+b)x+ab = 0
x²-(3-1)x+(-3) = 0
x²-2x-3 = 0
cubic polynomial,
(x²-2x-3)(x+1/3) = 0
x³+x²/3-2x²-2x/3-3x-1 = 0
3x³+x²-6x²-2x-9x-3 =3
3x³-5x²-11x-6 = 0
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