Question

find the curl of the vector yi+zj+xk​

Answer 1

Step-by-step explanation:

Since

∂F1∂x=0,∂F2∂y=x,∂F3∂z=1

we calculate that

divF=0+x+1=x+1.

Since

∂F1∂y=−1,∂F2∂x=y,∂F1∂z=∂F2∂z=∂F3∂x=∂F3∂y=0,

we calculate that

curlF=(0−0,0−0,y+1)=(0,0,y+1).

I hope this related answer is helpful.

Answer 2

Answer:

3

Step-by-step explanation:

The vector given is a position vector. The divergence of any position vector is always 3.