Find the current and potential drop on each resistor?
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Answer:
Given - V=20.0V,R
1
=5.0Ω,R
2
=2.0Ω,R
3
=1.0Ω,R
4
=2.0Ω
as all the resistors are in series combination therefore equivalent resistance will be ,
R=2.0+1.0+2.0+5.0=10.0Ω
total current in circuit (through each resistor) ,
I=V/R=20.0/10.0=2A
now , voltage drop across resistor 1 ,
V
1
=IR
1
=2×5.0=10.0V
voltage drop across resistor 2 ,
V
2
=IR
2
=2×2.0=4.0V
voltage drop across resistor 3 ,
V
3
=IR
3
=2×1.0==2×1.0=2.0V
voltage drop across resistor 4 ,
V
4
=IR
4
=2×2.0=4.0V
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