Question

find the current drawn from the battery by network of four resistors shown in the figure​

Answer 1

Answer:

I = 0.3 v

Explanation:

2 up ward & 2 down ward resistances are in series but mutually thay are parallel

R1 = 10 + 10

R1 = 20 ohm

similarly another       R2 = 20 ohm

R1 & R2 in series so

1 / R = 1 / R1 + 1 / R2

1 / R = 1 / 20 + 1 / 20

1 / R = 1 / 10

R = 10 ohm

V = 3 v

I = V / R

I = 3 / 10

I = 0.3 v