Find the current drawn from the battery by network of
four resistors shown in the figure.
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Answer:
0.3 A
Explanation:
For this sum, we need to first calculate the total resistance,
Here we have two 10 ohms in series and four of them in parallel with a set of two on either side
Resistance in each arm = 10+ 10 ohms = 20 ohms
Total resistance = R
For finding resistance in the wire for parallel connection, formula is
1/R = 1/R1 + 1/R2+ ........+ 1/Rn
1/R = 1/20 + 1/20 = 2/20 = 1/10
therefore,
R = 10 ohms
By Ohms Law,
V = IR
I= V/R = 3/10 A = 0.3 A
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