Question

FIND THE CURRENT DRAWN FROM THE BATTERY BY THE NETWORK OF FOUR RESISTORS SHOWN IN THE FIGURE

Answer 1

Answer:

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Answer 2

Answer:

Given: Potential difference=3V

1/R= 1/30+1/10 = 4/30

R=30/4 =7.5ohm

So by Ohms laws

V=IR

3=I×7.5

l=3/7.5

I=0.4A

So the value of current is 0.4 A

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