Question

Find the current drawn from the battery by the network of four resistors as 10ohm,10ohm,10ohm,10ohm​

Answer 1

first we need to find total resistance

ok ..... here you can see

3 resister of 10 ohms are in series

and one in parallel to it

so resistance of series =30ohms

and one resistance is now parellel to it

so you can write =

toatl resistance = (1/10+1/30)^-1

( 4/30)^-1 = 30/4ohms

now , potential difference is 3v

using ohms law

v=ir

3 = 30/4 ×i

total current = 0.4 ampere