Question

Find the current drawn in the given circuit

Answer 1

We have three resistors in series.so the effective resistance is 30ohm.

Then this imaginary resistor is in parallel connection with the lower resistor.

So the total resisistance is( 1÷30)+(1÷10)=0.43ohm

So by ohm,V=IR

So I=V÷R

=3÷0.43

=6.9amp

Answer 2

Answer:

resistance of the three conductors in series = 10+ 10+ 10= 30 ohms

R(p) = (30×10) ÷ (30+10)

= 15÷2

= 7.5 ohms

By Ohms law

V =IR

I= V÷R

= 3÷ 7.5

= 0.4 A

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Hope it helps