Question

Find the current flowing in the circuit......​

Answer 1

Answer:

effective ressistence = 15 ohm+15 ohm =30 ohm

I=V/R

I= 6/30

1/5

0.2 ampere

Answer 2

Required Solution:

Given:

• $\sf { R_1 = 15Ω }$

• $\sf { R_2 = 15Ω }$

• $\sf { Voltage = 6V }$

To calculate:

• Current flowing through the circuit (I)

Calculation:

Here, we will apply the formula of the Ohm's law that is :

• ${\underline {\boxed {\Large {\bf \gray { V= IR } }}}}$

Where,

• V = Potential difference/Voltage = 6V
• I = ? (Have to calculate)
• R = ?

Let's calculate the resistance first.

Since, resistors are connected in series combination.So,we'll apply the given formula below:

• ${\underline {\boxed {\Large {\bf \gray { R_s = R_1 + R_2...........R_n } }}}}$

$\sf { \longmapsto R_s = 15Ω + 15Ω}$

$\sf { \longmapsto R_s = 30Ω}$

• Resistance (R) = 30Ω

Now,

$\sf {\longmapsto V= IR}$

$\sf {\longmapsto 6 = I \times 30}$

$\sf {\longmapsto 6 = 30I}$

$\sf {\longmapsto I= \dfrac{6}{30} }$

$\sf {\longmapsto I= \dfrac{1}{5}A }$

Therefore, current flowing through the circuit is 1/5 ampere .

Verfication:

$\sf {\longmapsto V= IR}$

$\sf {\longmapsto 6 = \dfrac{1}{5} \times 30 }$

$\sf {\longmapsto 6 = 6 }$

Hence, verified!

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