Question

Find the current flowing through 0.5 Ω resistor and please give complete explanation and correct answer otherwise I will report

Answer 1

Answer:

CURRENT FLOW IS 1 AMPERE

Explanation:

THE EQUIVALENT RESISTANCE OF R2 AND R3 IS 4OHM SO ALL THE RESISTOR ARE IN SERIES

IF WE PUT RESISTOR OF 0.5 OHM THEN IT WILL ALSO CONNECT IN SERIES

AS WE KNOW THAT CURRENT IN SERIES IS EQUAL THROUGHOUT THE CIRCUIT

SO TOTAL RESISTANCE = R1 +(R2+R3)

4+4 = 8ohm

voltage = 8volt

I=V/R

I= 8/8

I= 1AMPERE