find the current flowing through 6 ohm resistor
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Explanation:
The given circuit act as a balanced wheatstons bridge[no current through the wire connecting the two resistor combination]
since it satisfies the condition 3/6=12/24=1/2.
net resistance,
3 and 12 are in series=15 ohm
6 and 24 are in series =30 ohm
this 15 and 30 are in parallel
net resistance=10 ohm
net current,V=IR
30V=I*10,I=3A
current in 6 ohm= current in 24 ohm since in series connection
branch 1 [3 and 12] and branch 2[6 and 24] are in same voltage due to parallel connection
current through the 6 ohm is 5 A
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