Question

find the current flowing through a cylindrical conductor, if the number of free electrons passing per second through its cross section is 2.5*10^9​

Answer 1

Answer:

4.01*10^-10 ampere

Explanation:

1 ampere=6.22*10^18 electron

so 2.5*10^9 electron will constitute 4.01*10^-10 ampere of current

Answer 2

The current flowing through a cylindrical conductor is $I=4\times 10^{-10}\ A$.

Explanation:

Given that,

Number of free electrons, $n=2.5\times 10^9$

We need to find the current flowing through a cylindrical conductor. We know that the electric charge flowing per unit time is called electric current such that,

$q=ne$

and

q = I/t, I is the current

So,

$\dfrac{I}{t}=ne$

$I=n\times e\times t$

$I=2.5\times 10^9\times 1.6\times 10^{-19}\times 1$

$I=4\times 10^{-10}\ A$

So, the current flowing through a cylindrical conductor is $I=4\times 10^{-10}\ A$. Hence, this is the required solution.

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Electric current

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