Physics, asked by mandalsibu484, 9 months ago

find the current flowing through the 2ohm resistor​

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Answered by chhotraysoren1971
1

Answer:

Here R1 : 16 ohm R2 : 16 ohm R3 : 32 ohm R4 : 2 ohm

Now , we know that 1/R: 1/R1 + 1/R2

so , 1/R : 1/16 + 1/ 32 , R : 32/3 , R : 10.6 ohms . Total resistence : 10.6 + 16 + 2 : 28.6 ohms .Now V : R/ I , I : V / R , I : 20 + 20 / 28.6 , I : 40 / 28.6 , I : 400/ 286 , I : 1.39 A

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