Question

Find the current flowing through the following electric circuit.

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Answer 1

Answer:

0.5 A

Explanation:  

V=IR    (OHM'S LAW)             ...(i)

R between 6 Ω, 1 Ω and 3 Ω:  

1 Ω and 3 Ω are in series

therefore,  

R (series) = 1 Ω + 3 Ω = 4 Ω

now, resistance between 6 Ω and 4 Ω, they are in parallel

therefore,  

1/ R (parallel) = 1/6 +1/4

                    = 2/12 + 3/12

                    = 5/12  

R (parallel) =  12/5  = 2.4 Ω

now resistance between 3.6 Ω, 2.4 Ω and 3 Ω. they are in series.

therefore,

R (series) = 3.6 Ω + 2.4 Ω + 3 Ω  

             =  9 Ω

now, putting values in (i)

4.5 = 9 I

I = 4.5/9

= 0.5 A   (0.5 ampere)