Question

Find the current i3 in the circuit shown below.
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Answer 1

Answer:

3 Ampere

Explanation:

Let,        i$^{1}$  denotes  5A

             i$^{2}$  denotes  2A

Then,

             i$^{1}$ = i$^{2}$ + i$^{3}$            [Current got divided in parallel resistor connection]

          5A = 2A + i$^{3}$

          3A = i$^{3}$

Answer 2

Solution:

here, as we can see from the circuit given

5A current is flowing through the resistance R1 , 2A current is flowing through the resistance R2 and i3 current is flowing through the resistance R3.

let, i1 be the current through the resistance R1.

      i2 be the current through the resistance R2.

      i3 be the current through the resistance R3.

given, i1 = 5A and i2 = 2A

now, from the K C L

 i1 = i2 + i3

 i3 = i1 - i2

 i3 = 5 - 2

 i3 = 3A