find the current in 1ohm resistor
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Explanation:1ampere
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Explanation:
Given Find the current in 1 ohm resistor
- Using Kirchoff’s law we get
- So – 6 + 3I1 + 1 (I1 – I2) = 0
- So 3I1 + I1 – I2 = 6
- Or 4 I1 – I2 = 6---------1
- So – 9 + 2 I 2 + 1(I 2 – I 1) + 3 I 2 = 0
- So – 9 + 2 I2 + I 2 – I 1 + 3 I 2 = 0
- Or – I1 + 6 I 2 = 9 ---------------2
- Solving 1 and 2 we get
- 4 I 1 – I 2 = 6
- -I 1 + 6 I2 = 9 multiply by – 4
- So 4 I 1 – I 2 = 6
- 4 I 1 – 24 I2 = - 36
- 23 I 2 = 42
- So I 2 = 42 / 23 Amperes
- Also I 1 = 45 / 23 A
- Now net current across 1 ohm resistance will be I 1 – I 2
- = 45 / 23 – 42 / 23
- = 3 / 23 A from Q to P
- = 0.13 A from Q to P
Reference link will be
https://brainly.in/question/9923987
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