Physics, asked by Anonymous, 11 months ago

find the current in 2 ohms resistor, refer to the following attachment ​

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Answers

Answered by AdorableMe
46

For the circuit on the left side,

  • Potential difference = 10 V
  • Resistance = 5 Ω

We know,

V = IR

⇒10 = I × 5

⇒I = 10/5

⇒I = 2 A

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For the circuit on the right side,

  • Potential difference = 20 V
  • Resistance = 10 Ω

We know,

V = IR

⇒20 = I × 10

⇒I = 20/10

⇒I = 2 A

As the 2 Ω resistor is connected with both the circuits in series, so the current flowing through the 2 Ω resistor is 2 - 2 = 0 A. (As the current of 2 A is reserved for the respective circuits, and don't flow beyond that.)

Answered by Anonymous
1

Explanation:

◙ For the circuit on the left side,

Potential difference = 10 V

Resistance = 5 Ω

We know,

V = IR

⇒10 = I × 5

⇒I = 10/5

⇒I = 2 A

◙ For the circuit on the right side,

Potential difference = 20 V

Resistance = 10 Ω

We know,

V = IR

⇒20 = I × 10

⇒I = 20/10

⇒I = 2 A

As the 2 Ω resistor is connected with both the circuits in series, so the current flowing through the 2 Ω resistor is 2 - 2 = 0 A. (As the current of 2 A is reserved for the respective circuits, and don't flow beyond that.)

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