find the current supplied by the cell in the circuit shown in figure
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Answered by
13
Answer:
Step-by-step explanation:
BOTH 10 OHMS R IN PARALLEL
R PARALLEL = 10*10/10+10
= 100/20
= 5 OHMS.
THIS 5 OHMS AND THE OTHER 5 OHS ARE IN SERIES.
R NET = 5+5
= 10 OHMS.
ACCORDING TO OHMS LAW
V = I*R
5 = I*10
I = 0.5 A.
THEREFORE THE CURRENT FLOWING THROUGH THE CIRCUIT IS 0.5 A.
HOPE THIS HELPS.
Answered by
2
Answer:
30 amperes
Step-by-step explanation:
1)First let's solve parallel resistance
10*10/10+10
=1
2)Now it is a series combination
5+1
=6
3)Now let's use I=VR
=5*6
=30
4)30 amperes given by battery
Hope it helps
Is it wrong??
Pls let me know in comments
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