Find the current supplied by the cell in the circuit
shown in Figure 4.E3.
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1
Answer:
Here all the resistors are in parallel and the equivalent network is shown in figure.
The equivalent resistance, R
eq
=(1/8+1/6+1/4+1/12)
−1
=(15/24)
−1
=8/5Ω
The current supplied by battery is I=
R
eq
V
=
8/5
24
=15A
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