Question

Find the current supplied by the cell in the
circuit shown in figure.
592



w
1052
mi
1092
5V​

Answer 1

Answer:

From figure:-

In Loop ABDA:-

V

1

=R

1

i

2

+R

3

(i

1

+i

2

)

⟹3i

2

+6i

2

=15

⟹i

1

+3i

2

=5

⟹i

1

=5−3i

2

-------(a)

In Loop BCDB:-

V

2

=R

2

i

1

+R

3

(i

1

+i

2

)

⟹6i

1

+3i

2

=30

⟹2i

1

+i

2

=10

⟹2(5−3i

2

)+i

2

=10 from equation (a)

⟹10−5i

2

=10

⟹i

2

=0

from equation (a):-

i

1

=5−3i

2

=5A

Current in branch BD=i

1

+i

2

=5A