Physics, asked by shiny55, 1 year ago

Find the current through 10 ohm resistance connected across ab​

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Answered by VedaantArya
127

Answer:

0A.

Explanation:

Method #1 (generalized):

Using effective EMF and Resistance in branch AB:

Effective EMF = (\frac{E_{1}}{R_{1}} + \frac{E_{2}}{R_{2}}) * R_{eq}

Note that here, the EMFs 10V and 5V have opposite polarity.

Effective EMF = (\frac{-10}{2} + \frac{5}{1}) * R_{eq}

Effective EMF = (0) * R_{eq} = 0 V.

Since there is no potential difference across AB, the current is zero.

Method #2 (not generalized):

Here, examining the outer loop ONLY - assuming that branch AB does not exist:

Total EMF = 10 V + 5 V = 15 V

Total resistance = 2 + 1 ohms = 3 ohms

Current = EMF/R = 15/3 A = 5 A

Going from A to B across 5 V:

V(A) + 5 V - (current)(1 ohm) = V(B)

V(A) + 5 V - (5 A)(1 ohm) = V(B)

V(A) + 5 V - 5 V = V(B)

V(A) = V(B)

So, the potentials at A and B are equal, hence even if there was a resistance across them, no current would flow through it.


shiny55: tq
shiny55: can I ask u one more question
VedaantArya: Sure.
shiny55: how to keep a pic of the question
VedaantArya: Didn't get that. Which did you mean:
1. Insert a picture in a question?
2. Download a picture from a question?
3. Screenshot a question?
sowmeshwar185: why did you take 5 as the emf? why not 10? orEeq?
VedaantArya: I'm not sure which part you're referring to.
In Method #2, I'm going across, as in, using Kirchoff's Laws on the loop formed by the middle branch, and the 5V battery.
Going across the 10V battery would yield the same result (Method #2).

Method #1 uses the Eeq technique, Method #2 doesn't require it.
Answered by sehrali3b
3

Answer:

hope it helps. mark as brainliest

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