Find the current through 10 ohm resistance using superposition theorm
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∴ RAB = Rth = 8 + 2 || 5 = 9.43 Ω Hence, the equivalent Thevenin's source with respect to terminals A and B is as shown in Fig. When 10 Ω resistance is reconnected across A and B, current through it is I = 6.24/(9.43 + 10) = 0.32 A
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