find the current through 4ohm resistor using thevenins theorem
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Writing down circuit equations, with given conditions, and marking three clockwise loop-currents as i1, i2 and i3. i1 = 5A, due to the current source of 5 Amp VA −VB = 6V, due to the voltage source of 6Volts i3 −i2 = 2A, due to the current source of 2 Amp. VA = (i1 −i2)2, VB = i3 × 4 With these equations, the unknowns can be evaluated. 2 (i1 −i2) − 4 i3 = 6, 2 (5 −i2) − 4(2 + i2) = 6 This gives the following values : i2 = − 2/3 Amp., i3 = 4/3 Amp. VA = 34/3 volts, VB = 16/3 volts
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