Question

Find the current through 7Ω in the network given below​

Answer 1

Explanation:

Resistors 1Ω, 3Ω and 2Ω are connected in series. So their equivalent resistance (let us denote it by Rs) is:

Rs=1+2+3=6Ω

resistors 6Ω and 6Ω are connected in parallel,

So, equivalent resistance =

R

s

1

=

R

1

1

+

R

2

1

=

6

1

+

6

1

=

3

1

R

s

=3Ω

So, like wise equivalent resistance of the circuit =

R

s3

1

=

3Ω+5Ω

1

+

8Ω

1

=

4Ω

1

R

s3

=4Ω

R

s4

=4Ω+7Ω+9Ω=20Ω

As current through the resistor 3Ω is 0.25A, So current through the resistor 6Ω will be also, 0.25A. As equivalent resistance is same for both place.

As per ohm' s law, I3=0.25+0.25=0.50A

As current through the resistor 5Ω is 0.50A, So current through the resistor 8Ω will be also, 0.50A. As equivalent resistance is same for both place.

As per ohm' s law, I4=0.5+0.5=1A

So, We can use Ohm's Law

V = IR

V=1*20=20V

Answer 2

Answer:

given in figure:- v = 5v

R= 7 ohms

formula:- I =V/R

I = 5/7

I = 0.71 A

hence 0.71 A current is pass through 7 ohms of resister.

Explanation:

Hope this will help you!