Question

Find the current through branch AB.

ASAP!!!!!!!!!!!!!!!!

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Answer 1

Answer:

Apply Kirchhoff's law

for loop 1:3i1 - 3i2 = 3 = i1 - i2 = 1(1)

for loop 2:(2+2+3) i2 - 2i3 - 3i1 = 0 = 7i2 - 2i3 - 3i1 = 0....(2)

for loop : (2+2)i3  −2i2  =0⇒2i 3  =i2...(3)

from (2) and (3),  7i2  −i2  −3i1  =0⇒2i2  =i1 ...(4)

from (1) and (4), 2i2 −i2  =1⇒i2 =1A  

put i2 =1 in (1) and (4),  i1  =1+1=2A  and i3  =0.5i2 =0.5A

Thus the current through branch AB =i1  −i3 =2−0.5=1.5A

Explanation: