Question

Find the current through the battery in each of the circuits shown in figure.
Figure

Answer 1

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Where is the figure?

Answer 2

Current in Circuit (a) is 1 A

Explanation:

Both diodes are forward biased.  

Thus the net diode resistance is 0.

$i= \frac {5}{5}$

= 1 A  

One diode is forward biased and other is reverse biased.  

Current passes through the forward biased diode only.

$i = \frac {V}{R_n_e_t}$

= $\frac {5}{10} + 0$

= $\frac {1}{2}$

= 0.5 A.