Question

find the currents in all branches of the networks shown a 4 ohm b 3 ohm e 25v f c 2 ohm d 20v​

Answer 1

Answer:

your answer

Explanation:

Resistors 122, 39 and 29 are connected in series. So their equivalent resistance (let us denote it by Rs) is:

Rs=1+2+3=622

resistors 69 and 62 are connected in parallel, So, equivalent resistance =

1

R$

1

+

12

R₁ R₂

Rs = 3Ω

1 1

+

=

13

6 6 3

So, like wise equivalent resistance of the circuit =

1

R$3

1

+

1 1

=

392+59 89 40

Feedback

Rs3 = 49

R$4 = 4Ω + 7Ω + 9Ω = 20Ω

As current through the resistor 392 is 0.25A, So current through the resistor 692 will be also, 0.25A. As equivalent resistance is same for both place.

As per ohm's law, 13-0.25+0.25=0.50A