Question

Find the curve surface area of a garden roller whose length and diameter are 1.5 m and 1.4 m respectively.how much area can it level in 200 revolution.

Answer 1

C.S.A= 2pie×r×h
=2×3.14×0.75×1.4
=3297/500
= 3297/500×200 revolutions
=1318.8 msq.

Answer 2

Given, length of the garden roller = 1.5 m

and diameter of the garden roller = 1.4 m

So, radius of the garden roller = 1. 4/2 = 0.7 m

Now, curved surface are of the roller = curved surface are of the cylinder

                                                  = 2πrh

                                                  = 2 *(22/7) * 0.7 * 1.5

                                                  = 2 * 22 * 0.1 * 1.5

                                                  = 6.6 m2

Now, in one revolution, area covered by roller = 6.6 m2

So, in 200 revolutions, area covered by roller = 6.6 * 200 = 1320.0 m2