Find the curved surface area and the total surface area of the cylinder for which :-
1 h= 30 cm and r =14 cm
2 h = 32 cm and r = 10.5 cm
3 h = 35 cm and r =21 cm
4 h = 5 m and r = 35 cm
Answers
Answer:
1) CSA = 2640 cm^2 , TSA = 3872 cm^2
2) CSA = 2112 cm^2 , TSA = 2805 cm^2
3) CSA = 4620 cm^2 , TSA = 7392 cm^2
4) CSA = 1100 cm^2 , TSA = 8800 cm^2
Step-by-step explanation:
1) h = 30 cm and r = 14 cm
CSA = 2πrh
= 2 x 22/7 x 14 x 30
= 2 x 22 x 2 x 30
= 2640 cm^2
TSA = 2πr (r + h)
= 2 x 22/7 x 14 (14 + 30)
= 2 x 22 x 2 (14 + 30)
= 88 (14 + 30)
= 88 x 44
= 3872 cm^2
2) h = 32 cm and r = 10.5 cm
CSA = 2πrh
= 2 x 22/7 x 10.5 x 32
= 2 x 22 x 1.5 x 32
= 2112 cm^2
TSA = 2πr (r + h)
= 2 x 22/7 x 10.5 (10.5 + 32)
= 2 x 22 x 1.5 (10.5 + 32)
= 66 (10.5 +32)
= 66 x 42.5
= 2805 cm^2
3) h = 35 cm and r = 21 cm
CSA = 2πrh
= 2 x 22/7 x 21 x 35
= 2 x 22 x 3 x 35
= 4620 cm^2
TSA = 2πr (r + h)
= 2 x 22/7 x 21 (21 + 35)
= 2 x 22 x 3 (21 + 35)
= 132 (21 + 35)
= 132 x 56
= 7392 cm^2
4) h = 5 cm and r = 35 cm
CSA = 2πrh
= 2 x 22/7 x 35 x 5
= 2 x 22 x 5 x 5
= 1100 cm^2
TSA = 2πr (r + h)
= 2 x 22/7 x 35 (35 + 5)
= 2 x 22 x 5 (35 + 5)
= 220 (35 + 5)
= 220 x 40
= 8800 cm^2
HOPE IT HELPS...
Answer:
1) 2640cm² and 3872cm² (2) 2112 cm²and 2805 cm² (3) 4620 cm² and 7392 cm² (4) 1100cm² and 8800cm2