Question

find the curved surface area and totka surface area of a cylinder with radius 4.2 cm and height 90 cm. pls help urgent​

Answer 1

Answer:

A≈2485.88cm²

r Radius

4.2

cm

h Height

90

cm

Solution

A=2πrh+2πr2=2·π·4.2·90+2·π·4.22≈2485.87943cm²

Step-by-step explanation:

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Answer 2

AnSwer -:

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TSA of cylinder-: 2586.88 cm^2

CSA of cylinder-: 2376 cm^2

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Explanation-:

Formula of Curved Surface Area of

cylinder-:

“CSA = 2 πr h”

Formula of Total Surface Area of

cylinder-:

“TSA = 2 π r(h+r)”

TSA -: Total Surface Area

π = 22/7 or 3.14

R = radius

H = height

CSA = Curved Surface Area

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Now ,

Given ,

Height of the cylinder-: 90 cm

Radius of the cylinder-: 4.2 cm

To find,

CSA and TSA of the cylinder.


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Formula of CSA of cylinder-:

“CSA = 2 πr h”

π = 22/7 or 3.14

R = radius = 4.2 cm

H = height = 90 cm

CSA = Curved Surface Area

Then,

2 x 22/7 x 4.2 x 90

2 x 22 x 54

= 2376 cm^2

Therefore,

CSA of cylinder-: 2376 cm^2

Formula of Total Surface Area of

cylinder-:

“TSA = 2 π r(h+r)”

TSA -: Total Surface Area

π = 22/7 or 3.14

R = radius = 4.2 cm

H = height = 90 cm

Now ,

2 x 22/7 x 4.2 ( 90 + 4.2)

2 x 22 x 56.52

= 2486.88 cm^2

Therefore

TSA of cylinder-: 2586.88 cm^2

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TSA of cylinder-: 2586.88 cm^2

CSA of cylinder-: 2376 cm^2

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Cylinder-: Cylinder is one of the basic 3d

shapes, which has two parallel circular

bases at a distance. The two circular

bases are joined by a curved surface, at

a fixed distance from the center.

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