find the curved surface area of 12 cylindrical pillars of radius 28cm and height 4m and also find out of painting of all pillars at the rate of rupee 8 per m sq.
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11
curved surface area = 2 × pi × r × h = 2 × 22/7 × 0.28 × 4 = 7.04 m2
curved area of 12 such cylinders = 7.04 × 12 = 84.48 m2
Cost = rs 84.48 × 8 = rs 675.84
COST IS RS 675.84 AND CURVED SURFACE AREA IS 84.48 CM2
curved area of 12 such cylinders = 7.04 × 12 = 84.48 m2
Cost = rs 84.48 × 8 = rs 675.84
COST IS RS 675.84 AND CURVED SURFACE AREA IS 84.48 CM2
Answered by
2
Answer:
Given,
r =28cm
= 28/100m
=0.28m
h =4m
≈ CSA of a cylinder = 2×22/7×r×h
= 2×22/7×0.28×4
=176/25
= 7.04 m
≈ CSA of 12 cylinder = 7.04×12
= 84.48 m
≈ At rate, painting of pillars = ₹ 8 per m sq. unit
= ₹ 8×84.48 m
= ₹ 675.84
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