find the curved surface area of a cone with base 5.25 cm and slant height 10 cm
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r=5.25cm
h=10cm
l^2=h^2+r^2
l=√5.25^2+10^2
l=√27.5625+100
l=√127.5625
l=11.294357 or 12
C.S.A of cone=πrl
=22/7x5.25x12
=198 sq.cm.
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h=10cm
l^2=h^2+r^2
l=√5.25^2+10^2
l=√27.5625+100
l=√127.5625
l=11.294357 or 12
C.S.A of cone=πrl
=22/7x5.25x12
=198 sq.cm.
hope it hlps u
follow me
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