find the curved surface area of a garden roller whose length is 1.5m and radius is 70 cm. how much area can it level in 200 revolutions?
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CSA = 2πrh
= 2*22*70*150/7
= 2*22*10*150
= 66000 cm²
= 6.6 m²
So it can level 6.6 m² area in 1 revolution
Area levelled in 200 revolutions
= 6.6*200
= 1320 m²
= 2*22*70*150/7
= 2*22*10*150
= 66000 cm²
= 6.6 m²
So it can level 6.6 m² area in 1 revolution
Area levelled in 200 revolutions
= 6.6*200
= 1320 m²
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