Question

Find the curved surface area of a garden roller whose length and diameter are 1.5 m and 1.4 m respectively. How much area can it level in 200 revolutions?

Answer 1

$\underline{\textsf{Given:}}$

$\textsf{Length of the roller is 1.5.m}$

$\textsf{Diameter of the roller is1.4 m}$

$\underline{\textsf{To find:}}$

$\textsf{The curved surface area and area can be levelled in 200 revolutions}$

$\underline{\textsf{Solution:}}$

$\textsf{Diameter of  the roller=1.4m}$

$\implies\textsf{Radius of the roller=0.7m}$

$\textsf{Curved surface area of the roller}$

$\mathsf{=2\,\pi\,r\,h}$

$\mathsf{=2{\times}\dfrac{22}{7}{\times}0.7{\times}1.5}$

$\mathsf{=2{\times}22{\times}0.1{\times}1.5}$

$\mathsf{=3{\times}2.2}$

$\mathsf{=6.6}\,\textsf{square meters}$

$\textsf{Area covered by the roller in 1 revolution}\mathsf{=1{\times}}\textsf{curved surfacce area of the roller}$

$\textsf{Area covered by the roller in 200 revolution=200}\mathsf{\times}\textsf{curved surfacce area of the roller}$

$\mathsf{=200{\times}6.6}$

$\mathsf{=1320}\;\textsf{square meters}$

$\underline{\textsf{Answer:}}$

$\textsf{Curved surface area of the roller is 6.6 square meters}$

$\textsf{Area covered by the roller in 200 revolutions 1320 square meters}$

Find more:

The curved surface area of a cylinder is 1320 cm² and its base had diameter 21 cm. Find the height and the volume of the cylinder.[Use π = 22/7]

https://brainly.in/question/15911784

Answer 2

Answer:

Given:

\textsf{Length of the roller is 1.5.m}Length of the roller is 1.5.m

\textsf{Diameter of the roller is1.4 m}Diameter of the roller is1.4 m

\underline{\textsf{To find:}}

To find:

\textsf{The curved surface area and area can be levelled in 200 revolutions}The curved surface area and area can be levelled in 200 revolutions

\underline{\textsf{Solution:}}

Solution:

\textsf{Diameter of the roller=1.4m}Diameter of the roller=1.4m

\implies\textsf{Radius of the roller=0.7m}⟹Radius of the roller=0.7m

\textsf{Curved surface area of the roller}Curved surface area of the roller

\mathsf{=2\,\pi\,r\,h}=2πrh

\mathsf{=2{\times}\dfrac{22}{7}{\times}0.7{\times}1.5}=2×

7

22

×0.7×1.5

\mathsf{=2{\times}22{\times}0.1{\times}1.5}=2×22×0.1×1.5

\mathsf{=3{\times}2.2}=3×2.2

\mathsf{=6.6}\,\textsf{square meters}=6.6square meters

\textsf{Area covered by the roller in 1 revolution}\mathsf{=1{\times}}\textsf{curved surfacce area of the roller}Area covered by the roller in 1 revolution=1×curved surfacce area of the roller

\textsf{Area covered by the roller in 200 revolution=200}\mathsf{\times}\textsf{curved surfacce area of the roller}Area covered by the roller in 200 revolution=200×curved surfacce area of the roller

\mathsf{=200{\times}6.6}=200×6.6

\mathsf{=1320}\;\textsf{square meters}=1320square meters

\underline{\textsf{Answer:}}

Answer:

\textsf{Curved surface area of the roller is 6.6 square meters}Curved surface area of the roller is 6.6 square meters

\textsf{Area covered by the roller in 200 revolutions 1320 square meters}Area covered by the