find the curved surface area of a right circular cone of volume 12936 cm cube and base diameter 42 CM.
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hey!!!
given diameter of the base of the circular cone = 42cm
therefore it's radius = 42/2 = 21cm
volume of the circular cone = 12936cm³
>> 1/3πr²h = 12936cm³
>> 1/3×22/7×21×21×h = 12936cm³
>> 22/3×3×21×h = 12936cm³
>> 22×21×h = 12936cm³
>> 462×h = 12936cm³
>> h = 12936/462
>> h = 28cm
the height of the circular cone is 28cm.
now, we have to find it's Length (slant height) to find the CSA of the circular cone.
l = √(r²+h²)
l = √(21²+28²)
l = √(441+784)
l = √1225
l = 35
therefore, the slant height (l) of the circular cone is 35cm.
CSA of the circular cone = πrl
= 22/7×21×35
= 22×3×35
= 2310cm²
cheers!!!
given diameter of the base of the circular cone = 42cm
therefore it's radius = 42/2 = 21cm
volume of the circular cone = 12936cm³
>> 1/3πr²h = 12936cm³
>> 1/3×22/7×21×21×h = 12936cm³
>> 22/3×3×21×h = 12936cm³
>> 22×21×h = 12936cm³
>> 462×h = 12936cm³
>> h = 12936/462
>> h = 28cm
the height of the circular cone is 28cm.
now, we have to find it's Length (slant height) to find the CSA of the circular cone.
l = √(r²+h²)
l = √(21²+28²)
l = √(441+784)
l = √1225
l = 35
therefore, the slant height (l) of the circular cone is 35cm.
CSA of the circular cone = πrl
= 22/7×21×35
= 22×3×35
= 2310cm²
cheers!!!
sushanths:
Thanks
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