Question

Find the curved surface area of a right circular cone whose slant height is 10 cm and Base is 7cm.

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Answer 1

Answer:

Curved surface area of right circular cone = πrl

Curved surface area of right circular cone = πrl22÷7×7×10

Curved surface area of right circular cone = πrl22÷7×7×10220

Step-by-step explanation:

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Answer 2

ANSWER

$\setlength{\unitlength}{1cm}\begin{picture}(6, 4)\linethickness{0.26mm} \qbezier(5.8,2.0)(5.8,2.3728)(4.9799,2.6364)\qbezier(4.9799,2.6364)(4.1598,2.9)(3.0,2.9)\qbezier(3.0,2.9)(1.8402,2.9)(1.0201,2.6364)\qbezier(1.0201,2.6364)(0.2,2.3728)(0.2,2.0)\qbezier(0.2,2.0)(0.2,1.6272)(1.0201,1.3636)\qbezier(1.0201,1.3636)(1.8402,1.1)(3.0,1.1)\qbezier(3.0,1.1)(4.1598,1.1)(4.9799,1.3636)\qbezier(4.9799,1.3636)(5.8,1.6272)(5.8,2.0)\put(0.2,2){\line(1,0){2.8}}\put(4.9,4){\sf{10 cm}}\put(3,2){\line(0,2){4.5}}\put(1.4,1.6){\sf{7 cm}}\qbezier(.185,2.05)(.7,3)(3,6.5)\qbezier(5.8,2.05)(5.3,3)(3,6.5)\put(3,2.02){\circle*{0.15}}\put(2.7,2){\dashbox{0.01}(.3,.3)}\end{picture}$

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$\sf Here \begin{cases} & \sf{Slant\:height, l = \bf{10\;cm}} \\ & \sf{Radius,r = \bf{7\;cm}} \end{cases}$

We have to find, Curved surface area of cone.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

We know that,

$\star\;{\boxed{\sf{\purple{C.S.A._{\;(cone)} = \pi rl}}}}$

where,

• l is slant height and r is radius of base of cone.

✇ Now, Putting value in Formula,

$\qquad\qquad:\implies\sf \dfrac{22}{ \cancel{7} }\times \cancel{7} \times 10$

$\qquad\qquad\;\;\;\;:\implies\sf 22 \times 10$

$\qquad\qquad:\implies{\boxed{\frak{\pink{220\;cm^2}}}}\;\bigstar$

$\therefore\;{\underline{\sf{C.S.A.\;of\;right\; circular\;cone\;is\; \bf{220\;cm^2}}}}$

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$\begin{gathered}\boxed{\bigstar{\sf \ Cone :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Cone= \dfrac{1}{3}\pi r^2 h \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ Cone = \pi r l \\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ Cone = \pi r (l+r) \\ \\ \\ \sf {\textcircled{\footnotesize4}} Slant \ Height \ of \ cone (l)= \sqrt{r^2+h^2}\end{gathered}$