Question

Find the curved surface area of a right circular cone whose height is 8 cm and base of radius is 6cm. *​

Answer 1

Answer:

• Curved surface area of right circular cone is 188.57 cm².

Step-by-step explanation:

GivEn:

• Height of right circular cone, h = 8 cm
• Radius of right circular cone, r = 6 cm

To find:

• Curved surface area (CSA) of the right circular cone?

Solution:

We know that,

(Slant height)² = (Radius)² + (Height)²

⇒ l² = r² + h²

⇒ l² = (6)² + (8)²

⇒ l² = 36 + 64

⇒ l² = 100

⇒ √l² = √100⠀⠀⠀⠀⠀ ❬(Taking sqrt. both sides)❭

⇒ l = 10 cm

∴ Thus, Slant height of right circular cone is 10 cm.

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Now,

We'll find Curved surface area of right circular cone,

★ CSA of cone = πrl

Here, we have,

• r = 6 cm
• l = 10 cm

⇒ 22/7 × 6 × 10

⇒ 22/7 × 60

⇒ 1320/7

⇒ 188.57 cm²

∴ Hence, Curved surface area of the right circular cone is 188.57 cm².

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⠀⠀⠀⠀⠀⠀Formulas related to cone :

• Total surface area of cone = πr(l + r)

• Volume of cone = ⅓πr²h

• Area of circular base of cone = πr²

Answer 2

Answer:

$\huge \bf \: Given$

• Height of cone = 8 cm
• Base of radius = 6 cm

$\huge \bf \: To \: find$

Curved surface area of a right circular cone

$\huge \bf \: Solution$

For this we have to first find slanght height.

$\sf \: {L}^{2} = {R}^{2} + {H}^{2}$

$\sf \: {L}^{2} = {6}^{2} + {8}^{2}$

${ \sf \: L}^{2} = { \sf \: 36}^{} + \sf \: 64$

$\sf \: {L}^{2} = 100$

$\sf \: L \: = \sqrt{} 100$

$\sf \: L \: = 10 \: cm$

Now,

Finding CSA of cone

$\huge \boxed { \sf \: CSA \: = \pi \: rl}$

$\sf \: CSA \: = \dfrac{22}{7} \times 6 \times 10$

$\sf \: CSA \: = \dfrac{22}{7} \times 60$

$\sf \: CSA = \dfrac{1320}{7}$

$\sf \: CSA \: = 188.57 {cm}^{2}$

Learn more

Cone - It is a 3 dimensional shape. It has 1 face, 0 edge or vertices. It is because it is round around the outside, it does not form any edges or vertices.