Question

Find the curved surface area of a roller whose length and diameter are 125 cm and 98 cm respectively. How such area of a playground can it level in 1000 complete revolutions.





please answer with solution.​

Answer 1

Answer:

cm=42cm

length of the roller (h)=120cm

∴ Area of the playground levelled in taking 1 complete revolution 2πrh

=2×227×42×120=31680cm

2

∴ Area of the playground

=31680×500=15840000cm

2

100×100

15840000

m

2

=1584m

2

Answer 2

Answer:

Curved surface area = 3.85 m²;Area of the playground in 1000 revolutions = 3850 m²

Step-by-step explanation:

Refer to the photo above.

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