Question

Find the curved surface area of one pillar if height of the pillar is 21m and radius of the base is 1m

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt Find\: the\: curved\: surface\: area\: of\: one \:pillar \:if \:height\\\tt of \:the\: pillar\: is \:21\:m\: and\: radius\: of\: the\: base\: is\: 1\:m.$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\bf Height\: of \:the\: pillar =21 \:m$
• $\bf Radius\: of\: the\: pillar =1 \:m$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\bf Curved\: surface \:area\: of \:the\: pillar$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\pink {\underline {\bf {\pmb {Curved\: surface \:area\: of \:the\: pillar}}}}}$

${\blue {\boxed {\boxed {\boxed {\green {\pmb {CSA_{(Cylinder)}=2\pi rh}}}}}}}$

• $\sf CSA=curved \:surface\: area \:of\: the\: cylinder$
• $\sf r=radius\: of\: the \:cylinder$
• $\sf h=height\: of\: the \:cylinder$

${\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}$

$\bf \implies CSA=2 \times \dfrac{22}{7}\times 1\times 21$

$\bf \implies CSA=2 \times \dfrac{22}{\cancel{7}}\times 1\times \cancel{21}$

$\bf \implies CSA=2\times 22\times 1\times 3$

$\bf \implies CSA=22\times 6$

$\implies {\blue {\boxed {\boxed {\purple {\mathfrak {A=132\:{m}^{2}}}}}}}$

${\underbrace {\red {\underline {\red {\overline {\red {\pmb {\sf {{\therefore} The\:curved \:surface \:area \: of \:the\:pillar\: is \:132\:{m}^{2}}}}}}}}}}$

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$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\sf Curved \:surface\: area \:of\: the\: cylinder=2\pi rh$

$\sf Total \:surface\: area \:of\: the\: cylinder=2\pi r(r+h)$

$\sf Volume \:of\: the\: cylinder=\pi {r}^{2}h$

Answer 2

Vacuoles store nutrients and water on which a cell can rely for its survival. They also store the waste from the cell and prevents the cell from contamination. Hence, it is an important organelle.