Find the curved surface area of right circular cone whose diameter of the base is 10cm and height is 12cm.
Answers
height=12cm
slant height=underroot of sum of squares of h and r.
=underroot of 144+25
=13cm
slant height is 13cm
then c.s.a of cone if pie×r×l =22/7×5×13 =204.28
The right circular cone has a curved surface area of 188.5 CM square
step by step explanation:
We are given the Diameter of the base of the right circular cone equal to 10 cm and we also know that the height of the cone is 12 CM.
since diameter is 10 cm radius will be half of diameter = 5 cm
r= 5,h = 12
To find the curved length L we need to apply Pythagoras theorem ,
{hypotenuse^2 = base^2 + height^2}
l^2 = 5^2 + 12^2
⇒ l = √(144+25) ⇒ l = 13 cm
Formula for curved surface area of cone is (sector's arc length/circle's circumference)x area of circle
⇒on putting the values the above formula can be simplified as πrl
⇒ (22/7) x 5 x 12 = 188.5 cm^2
The curved surface area of the cone equals 188.5 CM square
To know more:
Curved surface area of cone
https://brainly.in/question/15352031
Pythagoras theorem and Converse of Pythagoras theorem
https://brainly.in/question/13087481