Question

find the curved surface area of the cylinder having the following dimension radius of base = 56 cm and height = 1.5 cm​

Answer 1

Answer:

528

Step-by-step explanation:

csa= 2πrh

=2*22/7*56*1.5

=528

Answer 2

Step-by-step explanation:

Radius of base of the cylinder, r = 56cm

Height of the cylinder,. h = 1.5cm

So the curved surface area of the cylinder

$= 2\pi \: r \times h$

$= 2 \times \frac{22}{7} \times 56 \times 1.5$

$= 2 \times 22 \times 8 \times 1.5$

$= 528cm {}^{2}$