Question

find the curved surface area of the frustum of a cone, the diameters of
whose circular end are 30 m and 6 m and its height is 24 m.​

Answer 1

Answer:

Curved surface area of frustum = 3055 m²

Step-by-step explanation:

Let's assume that the big radius is R and small radius is r

Now, R = 30/2 = 15m

r = 6/2 = 3m

h = 24.

The slant height of the frustum cone is given by following equation

= √(h² + (R - r)²)

= √(24² + (15 - 3)²)

= 27 m. (approx.)

Now,

Curved surface area of frustum

= π(R + r)l

= 22/7 × ( 30 + 6 ) × 27

= 22/7 × 36 × 27

= 3055 m²

Hope it is helpful to you.

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