Question

Find the daimeter of circular cylinder if volume =44cm^3 and height 3.5 cm

Answer 1

Given :

• volume of cylinder =44cm³
• height = 3.5 cm

To find :

• diameter of circular cylinder

Formula Used :

$v = \pi {r}^{2} h$

$d = 2r$

where :-

• v = volume of cylinder
• r = radius
• h = height of cylinder
• d = diameter of base

Solution :

volume of cylinder =44cm³

height = 3.5 cm

$\implies \: v = \pi {r}^{2} h$

put :-

• v = volume
• r = radius
• h = height
• π = 22/7

$\implies \: 44 = \dfrac{22}{7} \times {r}^{2} \times 3.5$

$\implies \: 44 = \dfrac{22}{7} \times {r}^{2} \times \dfrac{35}{10}$

$\implies \: 44 \times\dfrac{7}{22} \times \dfrac{10}{35} = {r}^{2}$

$\implies \: 2\times\dfrac{1}{1} \times \dfrac{2}{1} = {r}^{2}$

$\implies \: 2\times2 = {r}^{2}$

$\implies \: 2cm= {r}$

We know :-

$d = 2r$

put r = 2 cm

$d = 2\times2$

$d = 4\:cm$

Answer :

diameter = 4 cm

________________

$\large\bf\red{Additional-Information}$

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = (4/3)πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²

_________________