Question

Find the de Broglie wavelength associated
with an alpha particle which is accelerated
through a potential difference of 400 V.
Given that the mass of the proton is
1.67 x 10-27 kg​

Answer 1

Answer:

PLEASE SEE THE ATTACHMENT.☝️

LAMDA = h / p ( DE BROGLIE WAVELENGTH FORMULA )

WHERE , h = PLANKS CONSTANT.

p = MOMENTUM.

LAMDA = WAVE LENGTH .

@AMINUL HOQUE