Question

find the de broglie wavelength of the electron in the first bohr orbit

Answer 1

Wavelength=h/mv
Here m=9.108*10^-31
v=2.188*10^8z/n
Therefore v=2.188*10^8*1/1
Since element is not given assume it to be hydrogen.
v=2.188*10^8
Wavelength=h/mv
=6.625*10^-34/9.1*10^-31*2.188*10^8
=0.3327*10^-11
=3.327*10^-12m