Question

Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cm. (Useπ=
7
22
​
)

Answer 1

Answer:

0.22°

Step-by-step explanation:

Radius (r) = 100 cm

Arc length (s) = 22cm

Angle subtended (y) =?

We know,

$s = r \times y \\ y = \frac{s}{r} \\ y = \frac{22}{100} = 0.22$

HOPE IT HELPS

Answer 2

$\huge{\bf{\underline{\blue{Given:}}}}$

• Radius of Circle = 100 cm

• Length of Arc = 22 cm

$\huge{\bf{\underline{\blue{To\:Find:}}}}$

• Degree measure of the angle subtended at the centre of a circle.

$\huge{\bf{\underline{\blue{Formula\:Used:}}}}$

• ${\bf{\boxed{r=\dfrac{l}{θ}}}}$

$\huge{\bf{\underline{\blue{Solution:}}}}$

Using Formula,

$\sf :\implies\:r=\dfrac{l}{θ}$

Putting Values,

$\sf :\implies\:100=\dfrac{22}{θ}$

$\sf :\implies\:θ=\dfrac{22}{100}$

$\sf :\implies\:θ=\dfrac{11}{50}\: radians$

Now,

$\sf :\implies\:θ=(\dfrac{11}{50}\times \dfrac{180}{\pi})°$

$\sf :\implies\:θ=(\dfrac{11}{5}\times \dfrac{18\times 7}{22})°$

$\sf :\implies\:θ=(\dfrac{11}{5}\times \dfrac{9\times 7}{11})°$

$\sf :\implies\:θ=(\dfrac{693}{55})°$

$\sf :\implies\:θ=(12\dfrac{33}{55})°$

$\sf :\implies\:θ=12°(\dfrac{3}{5}\times 60)'$

$\sf :\implies\:θ=12°36'$

Hence, The Degree measure of the angle subtended at the centre of a circle is 12°36'.

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