Question

Find the degree of dissociation and pH of 0.1M acetic acid, whose dissociation constant is 10^ -5 .​

Answer 1

Answer:

CH

3

COOH⇌CH

3

COO

−

+H

+

C

C−Cα Cα Cα

K

a

=

[CH

3

COOH]

[CH

3

COO

−

][H

+

]

=

C(1−α)

CαCα

=

1−α

Cα

2

=Cα

2

=1.8×10

−5

(1−α)

On solving we get α=0.0134

[H

+

]=Cα=0.00134

pH=−log([H

+

])

pH=2.87

Explanation:

hope it helps you bro have a great day